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how much mass would 1.62 moles of calcium carbonate have?

2006-10-26 14:37:49 · 1 answers · asked by Larson D 1 in Science & Mathematics ➔ Chemistry

1 answers

1.62 moles CaCO3 x molar mass
Ca= 40.01
C= 12.01
O=16 x 3
mm=100.02g/mol

1.62 moles CaCO3 x 100.02 g/mol= 162.03 = 162 g CaCO3

2006-10-26 15:48:44 · answer #1 · answered by loveboatcaptain 5 · 0⤊ 0⤋

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