67. Science and medicine. The time in seconds that it takes for an object to fall from rest is given by t = 1/4 square root of s in which s is the distance fallen. Find the time required for an object to fall to the ground from a building that is 800 ft high.
68. Science and medicine. Find the time required for an object to fall to the ground from a building that is 1400 ft high. (Use the formula found in exercise 67.)
2006-10-26 14:26:13 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
67.
time in seconds = t
distance fallen = s
s = 800 feet from top of building
t = 1/4 * (square root of s)
t = 1/4 *(square root of 800)
square root of 800 is 28.284271247461900976033774484194
t = 1/4 * (28.284271247461900976033774484194)
t = 7.0710678118654752440084436210485 seconds
68.
Same as 67, but s is different
s = 1400 feet
t = 1/4 * (square root of 1400)
square root of 1400 = 37.416573867739413855837487323165
t = 1/4*(37.416573867739413855837487323165)
t = 9.3541434669348534639593718307914 seconds
Hope I could be of help
2006-10-26 14:32:11 · answer #1 · answered by Clayton A 2 · 0⤊ 0⤋
67. looks pretty straightforward
the equation gives you t for any s, and they tell you s=800
t=1/4 * sqrt(800) = 7.07 seconds (the problem says the answer will be in seconds..probably too many significant figures but you can ponder that yourself
68. this is the same problem except you put 1400 in for s
you can do this, go for it
2006-10-26 21:34:22 · answer #2 · answered by enginerd 6 · 0⤊ 0⤋
67.)
1st find the sq root of 800, which is 28.28 (rounded)
multiply by 1/4. aka .25 =
t =7.07
68.) again sqrt of 1400 = 37.42
multiply = 9.355
t = 9.355
2006-10-26 21:36:22 · answer #3 · answered by drE-drE 2 · 0⤊ 0⤋
dont be a fool...stay in school
2006-10-26 21:34:23 · answer #4 · answered by uzurhead 3 · 0⤊ 0⤋