If the acceleration a(t) = 40 for all values of t, find a corresponding position function for which s(0) = 0 and v(0) = 40, all in appropriate units of measure. s(t) =
2006-10-26 14:13:44 · 3 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics
a(t)=40
Acceleration is the second derivative.
And velocity is the first of the standard position function
So find the anti deriv of this,
which would be
v(x)=40X+C
But we can solve for c the constant since we know v(0)=40
v(x)=40x+40
Then, to find the real standard position function, find the anti deriv one more time.
s(x)=20x^2+40x
I switched x and t sorry, its a habit.
2006-10-26 14:18:38 · answer #1 · answered by heyhelpme41 3 · 0⤊ 0⤋
20t^2+40t
i tihnk..
2006-10-26 21:19:01 · answer #2 · answered by Europa C 1 · 0⤊ 0⤋
do your own homework
2006-10-26 21:17:11 · answer #3 · answered by saadamin02 1 · 0⤊ 2⤋