. 25
Sigma (n^2 + n) =
n=1
2006-10-26 13:51:15 · 4 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics
Are you sure that's supposed to be a ".25" (one-fourth)?
If it's supposed to be just 25, then:
Sum of n from n = 1 to k is k*(k+1)/2 so that part is 25*26/2 = 325
Sum of n^2 from n = 1 to k is k*(k+1)*(2k+1)/6 so that part is 25*26*51/6 = 5525
So the total is 5850.
2006-10-26 13:55:41 · answer #1 · answered by Ben 2 · 2⤊ 0⤋
the sum of all the values of that equation from n=1 n =.25
(n^3)/3 + (n^2)/2 + n/6
.625/3 + .125/2 + .25/6
1.250/6+.375/6+.25/6
(1.5+.375)/6
1.875/6= 0.312
EDIt----------
I forgot the n at the end, lol
sooooo
(N^2+n)/2
.125+.25/
.075+.125
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.2+.312=.512
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just a guess however
2006-10-26 21:03:06 · answer #2 · answered by heyhelpme41 3 · 0⤊ 0⤋
nope....what the heck is sigma. I guess I havent made it that far yet.
2006-10-26 20:58:35 · answer #3 · answered by tearsnomore2005 2 · 0⤊ 0⤋
pie squared???? LOL....math is my favorite subject, but honey this is way past my IQ......good luck!
2006-10-26 20:53:51 · answer #4 · answered by Yahoo Answerer 4 · 0⤊ 0⤋