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A bullet is fired horizontally from a tower 45 m high at a speed of 350 m/s. How far downrange will the bullet travel?
i know the answers 1050m but how do you get it

2006-10-26 13:48:11 · 2 answers · asked by globesk8er999 1 in Science & Mathematics Physics

2 answers

if there is no wind resistance, then the acceleration due to gravity downwards will be 9.81m/s^2. it will have the same vertical drop a ball would if you drop it off the same tower. the vertical drop is defined by the eqaution

x(final)=x(0)+v(0)t+0.5at^2
45=0+0+0.5(9.81)t^2
t^2=45/4.9=9.17

t=3.03seconds this is the time it takes for the bullet to drop

now use this time and multiply by the horizontal speed

(3.03s)(350m/s)=1060m

or if you round the time down to 3 s, the answer is 1050m

this is the distance from the base of the tower that the bullet will land. the bullet will travel in a parabolic path from the top of the tower, so the total distance will be more

2006-10-26 13:54:59 · answer #1 · answered by Anonymous · 2 0

You got a very good answer from hanumaster. I agree on the solution completely. No need to wait for other answers.

2006-10-28 12:13:34 · answer #2 · answered by tul b 3 · 0 0

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