is any one great at math? because i need help?

Question

math problem: x^3+2x-2x-1
x-1

its actually it x-1 divided by x^3 + 2x - 1

Answer 1

Please note that your question is incomplete.If your problem is to factorise x^3+2x-2x-1,here it is: x^3+2x-2x-1 = x^3-1 =(x)^3-(1)^3 =(x-1) (x^2+x+1) . However if your problem is to divide X^3-1 by x-1 then factorise the numerator to (x-1)(x^2+x+1) as shown above,then cancel x-1 of numerator and denominator and you get the answer X^2+x+1

Answer 2

Your question is unclear. What is that dangling "x-1" supposed to represent? Are you asking what is x^3+2x-2x-1 divided by x-1?

Also, did you write your problem down correctly? Because you have x^3+2x-2x-1 which is really just x^3-1 (since 2x-2x=0)

EDITED TO ADD:

OK, well, x^3 + 2x - 1 divided by x-1 = x^2 + x + 1

Not sure me just giving you the answer is helpful though!

Here's how you solve it; you use long division!

Take (x-1) and divide it into (x^3 + 2x - 1). Your first term is x^2 (since x^2 times the 'x' in your 'x-1' will make x^3 that we can subtract from our (x^3 + 2x - 1) equation:

(x-1)*x^2 = x^3 - x^2, so
(x^3 + 2x - 1) - (x^3 - x^2) = x^2 + 2x + 1

Now divide (x-1) into x^2 + 2x + 1:

(x-1)*x = x^2 - x, so
(x^2 + 2x + 1) - (x^2 - x) = x-1

Now divide (x-1) into (x-1) ... easy, it's 1!

So, by long division, I determined that the answer was:
x^2 (my first term) + x (my second term) + 1 (my third term)

~ ♥ ~

Answer 3

If you are dividing it, then here is the answer.
x^3+2x-2x-1
x^3-1
-1/ 1 0 0 -1
-1 -1 -1
1 1 1 0
x^2+x+1
(I used synthetic division, if you are curious.)

Answer 4

what is the x- 1 is that part of the question?

Well, my brain hurts right now and I don't feel like doing any more math than I have to unless it's easy so .... sorry