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2006-10-26 13:31:20
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answer #1
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answered by joshmyersusf 1
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1
2006-10-26 20:35:38
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answer #2
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answered by robert w 3
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y = 1
plug 3 in for x to find what y would be:
2(3) + y = 7 - multiply 2 and 3 to get 6
6 + y = 7 - subtract 6 from both sides
y = 1
2006-10-26 20:34:30
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answer #3
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answered by Jeff 3
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2 x 3 + y = 7
6 + y = 7
6 + y - 6 = 7 - 6
y = 1
2006-10-26 20:39:54
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answer #4
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answered by chris b 1
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y equals 1.
2(3) + y= 7 plug 3 into x
6 + y=7 multiply 2 and 3
y=7 subtract 6 from 6 to get zero and then 6 from 7
to get 1
2006-10-26 20:35:28
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answer #5
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answered by Anonymous
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Y would be 1...Imagine if you will....2 multiplied by x which is 3=6, then add y which is 1..there you have 7 Good luck
2006-10-26 20:32:57
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answer #6
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answered by livewire 2
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Simply insert the value for x in the equation 2x3+y=7 and solve. As you can see, you need y to equal 1, right?
2006-10-26 20:33:24
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answer #7
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answered by deno 3
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plus in the 3, and then that makes:
2(3)+y=7
Then do the next step, 2x3:
6+y=7
think about the fact families. Which operation do you need to use to get your answers? Plug that operation into this problem:
7__6=y Get it? I'll let you do the rest.
2006-10-26 20:39:26
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answer #8
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answered by shiny and late 3
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The answer is 1.
2 x 3=6 + 1= 7
Good luck!
2006-10-26 20:38:12
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answer #9
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answered by Caelan's mom 3
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if x=3
2(3) + y = 7
6 + y =7
y = 7 - 6
y = 1
2006-10-26 20:34:06
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answer #10
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answered by Nabila 2
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