g(x) = 1 + 1/x , h(x) = 1 - 1/x , p(x) = 1/x - 1 , q(x) = -2/x .Then if f(x) = [g(x)]/[h(x)], what is f '(x)?

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2006-10-26 13:18:25 · 3 answers · asked by Doug 2 in Science & Mathematics ➔ Mathematics

g(x)=1+1/x= (x+1)/x
h(x)=1-1/x=(x-1)/x
g(x)/h(x)= (x+1)/x * x/(x-1)= (x+1)/(x-1)
f'[x]= ((x-1)-(x+1))/(x-1)^2= -2/(x-1)^2

2006-10-26 13:22:38 · answer #1 · answered by Greg G 5 · 0⤊ 0⤋

2006-10-26 13:21:14 · answer #2 · answered by Anonymous · 0⤊ 0⤋

absolutely nothing.

2006-10-26 13:19:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋