help with a math scale problem?

Question

ok i have no i diea how to do this, but i need to find how much each scale ='s so the first scale weighs 24 and there are 2 spheres, 2 cubes, and 2 cylanders. The second scale weighs 21 and theres 1 cylinder, 1 cube, 1 sphere, and 1 tall prism. The third scale is 28, there are 2 cylinders, and 2 tall prisms. On the last scale it is 23, it has 1 tall prism, 1 cylinder, and 3 cubes.....i need to figure out each shape in algebraic form i just dont kno how sooo thank you in advance

Answer 1

Let A = sphere, B = cube, C = cylinder, D = prism

Since 2A + 2B +2C = 24, divide by 2 to get A+B+C = 12

Now your second scale has A+B+C+D = 21. Since you know from the first scale that A+B+C = 12, you can subtract this from your second scale's equation to get D=9.

The third scale is 2C + 2D = 28. Since you know D=9, you can solve for C (2C=10, so C=5).

The last scale is D + C +3B = 23. You know D and C already (9 and 5), so 3B = 9, so B = 3

Finally, let's figure out A. From the second scale, we know A+B+C+D = 21. And we know D=9, C=5, B=3 ... so that means A=4

HTH! :-)

Answer 2

24=2 spheres, 2 cubes & 2 cylinders therefore
1 sphere, 1 cube and 1 cylinder would equal 12

21=1 cylinder, 1 cube & one sphere(12) and 1 tall prism so if you take 21 minus 12 that means a tall prism equals 9

28=2 tall prisms (2 times 9 = 18), and 2 cylinders so then you take 28 minus the 18 would leave 10 for the 2 cylinders so one cylinder would be 5

23= 1 tall prism (9) , 1 cylinder,(5) and 3 cubes. so 23 minus 9 for the prism and minus 5 for the cylinder leaves 9 for the three cubes. so then you know one cube would be 3.

Now you put it into algebraic format.

Answer 3

The first step is to give each seperate object an algebraic symbol, eg a,b,c,d. Then rewrite each equation in this new form;

Sphere = a
cube = b
cylinder = c
tall prism = d, so;

2a+2b+2c=24
1a+1b+1c+1d=21
2c+2d=28
1d+1c+3b=23

The first and third equations can be simplified by dividing each bit by 2, so 1a+1b+1c=12 & 1c+1d=14.

From the second equation and the first simplified one, we can find the value of d;
1a+1b+1c=12 & 1a+1b+1c+1d=21, then 1d=9
Also 1c+1d=14, and d=9 so c must = 5.

As 1d+1c+3b=23, and d+c=14, then 3b=9, so b=3.

As a+b+c=12, and b=3 and c=5, a= 12-3-5=4

Hence, sphere=4, cube=3, cylinder=5, and tall prism=9

Answer 4

Set up simultaneous equations for each scale and solve for the variables
24=2sphere+2cube+2cylinder
21=1sphere+1cube+1cylinder+1prism
28=2cylinder+2prism
23=1cylinder+3cube

multiply the second by 2
42=2sphere+2cube+2cylinder+2prism
subtract the first
-24=-2sphere-2cube-2cylinder
42-24=2prism
9=prism
plug this into the third:
28=2cylinder+18
5=cylinder
plug this into the last
23=5+3cube
6=cube

use the first to compute the sphere
24=2sphere+2cube+2cylinder
24=2sphere+12+10
1=sphere
check using the second
21=1sphere+1cube+1cylinder+1prism
21=1+6+5+9
21=21

j

Answer 5

0.01 meter = 1 cm 875m / 0.25m = 3500 0.05m(3500) = 175 m

Answer 6

24=2sp+2cu+2cy
21=1cy+1cu+1s+1tp
28=2cy+2tp
23=1tp+1cy+3cu

sp=
cu=
cy=
tp=


smthn like that idk