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focus is( -4, 3 multiplied by squareroot of 3)

2006-10-26 11:01:59 · 3 answers · asked by zenith 1 in Science & Mathematics Mathematics

3 answers

Centre =(-4,1), Vertex =(-4,7), focus=(-4,3*(3)^.5)
Distance between vertex & centre=a(say)=7-1=6 units
Distance between vertex & focus=ae=3*(root 3)-1 units, e=eccentricity of the conic.
e=ae/a= [3*(root 3)-1]/6= 0.7<1
hence, the conic is an ellipse.

we see, that the abcissae of center, vertex & focus are same, while the ordinates are different. Hence, the major axis of the ellipse is parallel to x-axis.

the general equation of such an ellipse is,
(y-A)^2/a^2+(x-B)^2/b^2=1, whose centre is(A,B)
& b^2=a^2(1-e^2)
in case of our ellipse, solving we get,
b^2=8+6*(root 3)

hence the equation of the conic is,
[(y-1)^2]/36+(x+4)^2/[8+6*( 3)^(1/2)]=1 [a=6]

there may remain mistake in calculation, but I think you have understood the method. So please check the solution.

2006-10-30 04:54:57 · answer #1 · answered by s0u1 reaver 5 · 0 0

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2016-12-08 22:06:26 · answer #2 · answered by Anonymous · 0 0

42

2006-10-26 11:18:44 · answer #3 · answered by Christy M 3 · 0 1

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