Get 10 points by solving an Algebra 2 problem?

Question

Find the zeros of the function by rewriting the function in intercept form.
3x^2-2x=5+y

SHOW WORK PLEASE

Answer 1

for y set x's = 0:

y(0) = 3(0)^2 - 2(0) - 5
y(0) = -5

for x set y = 0:

0 = 3x^2 - 2x - 5
0 = (3x-5)(x+1)
-now solve for 3x-5 = 0
x = 5/3
-now solve for x+1 = 0
x = -1

so y = -5
and x = 5/3 & -1

Answer 2

y=3X^2 -2X -5
0=3X^2-2X -5

using the quadratic formula:

{the above equation is of the form 0=aX^2 + bX + c, where a=3, b= -2, and c= -5, and the solution is:

X1= (-b +sqrt(b^2 - 4xaxc))/(2xa) and
X2= (-b - sqrt(b^2 - 4xaxc))/(2xa)

so let's sub in our coeficients and solve for X}

X1=(2+sqrt(2x2-4x3x(-5)))/(2x3)

X2=(2-sqrt(2x2-4x3x(-5)))/(2x3)

I dont have a calculator, so you carry out the calculation, carefully

Answer 3

y = 3x^2 - 2x -5

then, solve it using the quadratic formula