x^2 + 5x + 6 / x^2 + 4x + 4
/
x^2 - 9 / x^2 - 4
2006-10-26 10:10:34 · 6 answers · asked by Silentspeedster 2 in Science & Mathematics ➔ Mathematics
Simplify and state restrictions
2006-10-26 10:14:34 · update #1
This is one equation, correct? Factor everything first:
(x+3)(x+2) / (x+2)(x+2)
/
(x+3)(x-3) / (x+2)(x-2)
Then, to get rid of the denominator, flip it and get everything together:
(x+3)(x+2) (x+2)(x-2) / (x+3)(x-3) (x+2)(x+2)
Finally, eliminate the factors that appear on both the top and the bottom. You are left with:
(x-2) / (x-3)
2006-10-26 10:25:06 · answer #1 · answered by Anonymous · 0⤊ 0⤋
(x-2) / (x-3)
2006-10-26 17:15:58 · answer #2 · answered by cmadame 3 · 0⤊ 0⤋
(x+2)*(x+3) / (x+2)*(x+2)
(x+2) cancels out
leaving: (x+3) / (x+2)
2006-10-26 17:25:34 · answer #3 · answered by Lo 1 · 0⤊ 0⤋
(x+3)(x+2) / (x+2)(x+2)
(x+3) / (x+2)
x â -2
(x-3)(x+3) / (x-2)(x+2)
x â -2
x â 2
2006-10-26 17:14:33 · answer #4 · answered by c00kies 5 · 0⤊ 0⤋
I am intreperting it as a fraction over a fraction?
(x+3)(x+2) / (x+2)(x+2)
------------------------------ <-- my fraction bar
(x+3)(x-3) / (x+2)(x-2)
So reducing, canceling and performing a little mathmagic we get...
(x-2) / (x-3)
2006-10-26 17:18:19 · answer #5 · answered by iggry 2 · 0⤊ 1⤋
The answer is "absolute zero"...
2006-10-26 17:12:43 · answer #6 · answered by Kiowa1 5 · 0⤊ 0⤋