2006-10-26 10:08:30 · 5 answers · asked by mike s 1 in Science & Mathematics ➔ Mathematics
x² + y² - 4x - 12y - 9 = 0
So x² - 4x + y² -12y = 9
Thus (x² - 4x + 4) + (y² -12y + 36) = 9 + 4 + 36 (on completing the squares)
ie (x - 2)² + (y - 6)² = 7²
This is a circle centre (2, 6) radius 7
2006-10-26 10:33:46 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
That's a equation which describes a circle or an ellipse. Adjust it with the completion of squares so that you get something like (x+-a)^2 (y-b)^2 + c= Radius of the circle.
2006-10-26 17:18:07 · answer #2 · answered by Anonymous · 0⤊ 0⤋
the square root of this equation can be found by observing the ring of debris around uranus and dividing it by the dirivitave of the nekie index and adding 3.
2006-10-26 17:14:24 · answer #3 · answered by dread pirate lavenderbeard 4 · 0⤊ 0⤋
What are you trying to do with the equation?
2006-10-26 17:15:56 · answer #4 · answered by Anonymous · 0⤊ 0⤋
>:O
2006-10-26 17:10:22 · answer #5 · answered by beckray 4 · 0⤊ 0⤋