how would you find the slope and y-intercept in the following equation: y=(2-a)x+a
2006-10-26 09:57:42 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The equation is in slope-intercept form.
y = mx + b, where m is the slope and b is the y-intercept.
The slope is just the number in front of x. In this case it is 2-a.
The y-intercept is a.
Answer: slope = 2-a and y-intercept = a
2006-10-26 10:04:00 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋
The y intercept is what y equals when x = 0, so that is "a". The slope is the number in front of x, so that is (2-a)
2006-10-26 17:05:15 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Equation of a line
y = mx + b m = slope, b = y intercept
m = 2-a
Find the y intercept by setting x = 0
y = (2-a) * 0 + a
which is a or simply b = a
2006-10-26 17:07:17 · answer #3 · answered by Up_In_Smoke 2 · 0⤊ 0⤋
y = mx + b
slope: m = (2-a)
y - int: b = a
2006-10-26 17:07:43 · answer #4 · answered by c00kies 5 · 0⤊ 0⤋