Systems of Equations?

Question

Will you please help me?


Solve Algebraically

2x+3y=17
3x-2y= -0.5



-xoxox Shiloh

Answer 1

You asked this question earlier. Did you even bother to look at the answer?

Answer 2

Multiply the first equation by 3, and the second equation by 2:

6x + 9y = 51
6x - 4y = -1

to get the coefficients of x to be the same.

Now subtract the first equation from the second:

6x + 9y = 51
-13y = -52

Now you can solve the second equation for y: y = -52/-13 = 4. Then substitute y=4 into the first equation to obtain x = 5/2.

Another way to solve it is to solve one of the equations for x (in terms of y), and then substitute that expression for x into the other equation and solve it for y. I didn't do that here because there would be fractions and it would get messy.

Answer 3

Multiply first equation by 2 and second by -3 to give both the same coefficient for y:

4x+6y=34
-9x+6y=1.5

Subtract second equation from first:
13x = 32.5

Solve for x:
x = 32.5/13 = 2.5

Insert x into equation 1 and solve for y:

5+3y = 17
3y = (17-5) = 12
y = 4

Answer 4

ahh i wish i could just write this out instead of typing it but here you go

2x+3y=17
3x-2y=-.5

you want to get it so that you can eliminate either x or y so
(-3) 2x+3y=17 (-3)
(2) 3x-2y=-.5 (2)
-----------------------
what i did was i took the least common multiple or 2 and 3 , 6

so now you have:
-6x-9y=-51
6x-4y=1
----------------
-13y=-50
divide by -13 to get +4=y
now plug 4 in for y in one of the equations 2x+3(4)=17
now 2x+12=17
minus 12
2x=5
so x=2.5
x=2.5 y=4

Answer 5

To solve this, you need to eliminate one variable. I eliminated X.

6x + 9y = 51
6x - 4y = -1

13y=52

y = 4

6x + 9(4) = 51
6x = 51 - 36
x = 15/6 = 2.5

y is 4, x is 2.5
(2.5, 4)

Answer 6

3X 2x+3y=17
2X 3x-2y=-0.5

6x+9y=17
- 6x-4y=-0.5
0x 5y=16.5
y=16.5/5y

sub yinto first equation to get x

Answer 7

x=2.5, y=4