A rocket is used to place a synchronous satellite in orbit about the earth. What is the speed of the satellite

Question

A rocket is used to place a synchronous satellite in orbit about the earth. What is the speed of the satellite in orbit?

Answer 1

At a radius of 42241 km from earth's center, a circular orbit takes 24 hours exactly, at a speed of 11,058.7 kph or 6871.6 mph.

Answer 2

it depends on the height of the satellite. The higher it is, the more speed it needs. It should have the same orbital speed as the earth, so that seen from the earth the satellite appears to be standing still. Therefore it also depends on how many miles from the equator the satellite will circle above the earth. Speeds are less the farther you are from the equator. So you need a lot more info than this :)

Answer 3

Everybody but cirric is dead wrong. Satellites go slower as they get higher. And there's only one geosynchronous orbit. 22,300 miles up, or 26,300 from the center of the earth. The only thing cirric forgot to do was double that. The diameter of the orbit is twice the distance from there to the earth's center. So take 26,300 times 2 times pi, and that's how far the satellite has to go in one day. Divide by 24 for mph.

Answer 4

to unravel this challenge you want to charm to close the radius of the satellite tv for pc from the midsection of the earth then you definitely might want to apply the formulation speed= 2?R /T (Equation #a million) First you should understand that the centrifugal pressure from the satellite tv for pc must be balanced by technique of the gorgeous pressure between the earth and the satellite tv for pc so Centrifugal pressure =[(Mass of satellite tv for pc) x (speed)²] / Radius pleasing pressure = G ×(mass of earth) x (mass of sat) /(Radius)² the position G is the prevalent consistent Set those 2 equations equivalent to at least one yet another and confirm for the the speed (mass of the satellite tv for pc cancels out) and also you ultimately end up with speed = ?[G x ( Mass of Earth ) ] /Radius yet from Equation #a million speed = 2?R/ T So set those 2 equations equivalent to at least one yet another 2?R/T = ? [GxMass of Earth ] / R (R is Radius ) And confirm for R gives you R = ?[G x Mass of earth x T² ]/ 4?² G = 6.67e-11 ; mass of earth = 5.98e24 ; Time = 86400 seconds ( the type of seconds in a unmarried day as it really is the time for one orbit around the earth even if it really is transferring synchronously with the earth) provides R = 4.225 e7 Then change decrease back in Equation #a million V = 2?R / T gives you 3072.5 meters/sec

Answer 5

To solve, you need the radius of the the orbit from the center of the earth. this requires two formulas - V = 2 pi *R/ T and V = sqrt( G*M/R) where M is the mass of the Earth and G is the universal constant and R is the radius you are looking for and T is the time of one rotation - 24 hours which in seconds is 86400
Set the two equations equal to each other and solving for R you get

R = cube root of G*M*Tsquared/4 Pi squared
Use
G= 6.67e-11; M= 5.98e24; T = 8.64 e4
Then R = 4.23e7
Then plug back in to V = 2Pi*R/T gives you 3075 m/sec

Answer 6

Hi Geosynchronous orbits are about 23,000 miles high and the Earth is about 4,000 in radius. 27,000 times pi divided by 24 hours is your answer.

Answer 7

Most sattelites in the Clark Belt are traviling about 27,000 x Pi divided by 24. Which at my calculations comes out as 3532.5 mph. I could be wrong but I kinda doubt it.

Answer 8

the actual answer is going to be v= sqroot Gravational constant * Mass of Earth / radius
so (6.67^10-11 * 5.98*10^24)/(4.23*10^7) and that answer you will have to square root.

Answer 9

hey, how about this one to wrap your head around. speed in the terms you mean is defined by an object in relation to earth. in space there is no (nearly no) atmosphere, and not many other things - IT HAS NO SPEED, IT IS STATIONARY

Answer 10

It depends on the distance from the earth.