The question is an elevator lifts 1000 pounds 50 feet in 30 seconds. Assuming 100 % efficiency how much horsepower does it develop while lifting? Is there a formula that I am missing for this? Anty help is greatly appreciated.
2006-10-26 08:35:13 · 5 answers · asked by michelle p 2 in Science & Mathematics ➔ Mathematics
potential energy=mgh
=(1000/2.204)(9.8)
(50*12/254)joules
=(1000/2.204)(9.8)
(50*12/254)/30watts
divide by 746 you get the horse power
2006-10-26 08:40:03 · answer #1 · answered by raj 7 · 0⤊ 0⤋
Force x distance is the work done/30 is the power. Here force = mg= 1000xg poundals/seconds.
So it is 1000xgx50/30 footpoundals/sec.
Covert this to HP, see how many fps makes one HP and divide by that. I think the divisor is 553. Chaio
2006-10-26 16:00:01 · answer #2 · answered by Mathew C 5 · 0⤊ 0⤋
Horsepower is energy divided by time. Calculate the change in potential energy, divide by the time period to get the average power.
1 HP is 745.6999 watts
2006-10-26 15:39:14 · answer #3 · answered by arbiter007 6 · 0⤊ 0⤋
Power (P) = Work Doné/time
P = mgh/t = 1000*32*50/30 =53333.3ft.lb/s
Now 1HP = 550ft.lb/s
Use this conversion factor to find power developed in HP
P (HP) = 53333.3ft.lb/s/550= 97
2006-10-26 15:58:01 · answer #4 · answered by quark_sa 2 · 0⤊ 0⤋
when you talk about horse power output you must tell us about its voltage source and loaded current or how many kw to calculte the result
2006-10-26 15:49:54 · answer #5 · answered by lostship 4 · 0⤊ 0⤋