The sum of three consecutive integers is 40 more than the smallest. What are the intergers?
Cant figure it out!
2006-10-26 06:31:49 · 4 answers · asked by Anonymous in Education & Reference ➔ Teaching
ok -
The sum of three ODD integers is 40 more than the smallest. What are the intigers
Domain for the smallest [13,17,25]
2006-10-26 06:47:26 · update #1
Here's the working out.
x = smallest integer
x + 1 = next integer
x + 2 = highest integer
So:
x + x + 1 + x + 2 = x + 40 (40 more than the smallest integer)
3x + 3 = x + 40
2x = 37
x = 18.5
Unless the answer's 18.5, 19.5 and 20.5 (the sum gives you 57.5, 40 more than 18.5), then there's something wrong with the question. I know they're not whole integers, but that's the only possible solution.
2006-10-26 06:44:59 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The second two numbers have to add up to 40. Come up with two consecutive odd numbers that add up to 40. Those are the last 2 numbers. The first number is the odd number that comes before them.
2006-10-26 07:16:46 · answer #2 · answered by romulusnr 5 · 0⤊ 0⤋
x + (x+1) + (x+2) = x + 40
3x + 3 = x + 40
2x =37
x = 18.5 not an integer
2006-10-26 06:44:33 · answer #3 · answered by Amanda 4 · 0⤊ 0⤋
19+20+21=60
This is the closest I could get, but it is 41 difference
or
18+19+20=57
Difference is 39
Sorry no 40.
2006-10-26 06:38:02 · answer #4 · answered by jasonheavilin 3 · 0⤊ 0⤋