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13 answers

Let the temp be t deg F Or C( doesn't matter cause in both scales the temp is the same)
hence, t/5 = (t-32)/9
or, 9t=5t - 160
or, 4t = -160
or, t = -40
Hence the temp. is -40 deg c or -40 deg F

2006-10-26 18:23:49 · answer #1 · answered by s0u1 reaver 5 · 0 0

In general, F = (9/5) C + 32... this is how one would "translate" between the two scales. To calculate where they are the same, just substitue one letter in for the other and solve for that letter. For example...

C = (9/5) C + 32
(5/5) C = (9/5) C + 32
-4/5 C = 32
C = -5/4 * 32 = -40

2006-10-26 06:11:52 · answer #2 · answered by Kyrix 6 · 1 0

Wow, all these people that know the formula for converting Fahrenheit to Centigrade! I'm impressed!

And here all along I thought it was just common knowledge the scales crossed at -40

2006-10-26 06:16:30 · answer #3 · answered by lowflyer1 5 · 0 0

Remember the formula

c/5=(F-32)/9
where c=temp in centigrate
F=temp in fahrenheit
in your case, c=F

=>c/5=(c-32)/9
=>9c=5c-160
=>4c=-160
=>c=-40 deg. cen=-40 deg. far.

2006-10-26 06:57:29 · answer #4 · answered by sushant 3 · 0 0

(x-32)*5/9=x
3x-160=9x
4x=-160
x=-40
at -40* both the Celsius and Fahrenheit thermometer will read the same
i.e.- 40*C=-40*F

2006-10-26 06:09:34 · answer #5 · answered by raj 7 · 0 0

there cannot be same temp in Fahrenheit as well as Celcius. for ex. 0 C = 32 F and 0 F = -17.7 C. our body temp: 98.4 F = 36.8 C

2006-10-26 06:13:57 · answer #6 · answered by rdhinakar4477 3 · 0 1

the relationship between feh. and cel. is:

F=1.8 C+32

putting F=C, then we have:

-0.8 F=32

Which is: F=C= -40

2006-10-26 06:09:35 · answer #7 · answered by mozakkera 2 · 2 0

C / 5 = (F-32)/9

for C=F,
C/5 = (C-32)/9
or, 9C = 5(C-32) = 5C - 160
or, 9C-5C = -160
or, 4C = -160
or, C = -40

2006-10-26 06:11:51 · answer #8 · answered by The Potter Boy 3 · 0 0

(F-32)/C=9/5
AT SAME TEMP. LET F=C=X
(X-32)/X=9/5
SO X=-40
X=-40C OR -40F

2006-10-26 23:40:46 · answer #9 · answered by shaurya_coolman 1 · 0 0

-40°F is -40°C

2006-10-26 06:08:27 · answer #10 · answered by Prof. Frink 3 · 0 0

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