Given: O is the midpoint of segment BC
Triangle AOB is isos with segment OA = seg. OB
Prove: Triangle AOB is isosceles
2006-10-26 04:07:48 · 4 answers · asked by 2 days after my B day :) 2 in Science & Mathematics ➔ Mathematics
Diagrams would work better, but I shall try my level best to put the answer in as simple words as possible.
I first sum up all given info
OB = OC
OA = OB
Therefore, OA = OB = OC
As OA and OB, the opposite sides of triangle AOB are equal,
Triangle AOB is isosceles.
2006-10-26 04:22:55 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
I agree too ! ! ! You said AOB right? not AOC. If it's AOC, OA is equal to OB as given. OB is also equal to OC because O bisects BC. In short, OA=OB, OB=OC; therefore OA=OC. Then, AOC is isosceles
2006-10-26 11:16:09 · answer #2 · answered by Binangkaw 2 · 0⤊ 0⤋
as the sides OA and OB ARE EQUAL THEN AOB IS ISOCELES
AS OB=OC
AND OB=OA
OC=OA
SO, TRIANGLE AOC IS ISOCELES
2006-10-26 11:14:29 · answer #3 · answered by HEMNATH 2 · 0⤊ 0⤋
I agree! :-p
2006-10-26 11:08:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋