2006-10-26 03:24:58 · 4 answers · asked by mary h 1 in Science & Mathematics ➔ Chemistry
you guys are awesome, some of the brains on this site astound me :-) you smarty-smarty's!! thanks so much!!!
2006-10-26 03:44:17 · update #1
K2Cr2O7 + 4H2SO4 =
K2SO4 + Cr2(SO4)3 + 3[O] + 4H2O
ch3ch2ch2oh --->[O]---> ch3ch2cho ---> ch3ch2cooh
if you take excess of K2Cr2O7(an oxidising agent) then the aldehyde will oxidise to form the acid
2006-10-26 04:31:41 · answer #1 · answered by Charu Chandra Goel 5 · 2⤊ 1⤋
The main organic reaction product will be CH3CH2CHO, i.e. propanal (older name: propionaldehyde). The main organic by-product will be CH3CH2COOH, i.e. propanoic acid. The ratio of acid to aldehyde will depend on the temperature of the reaction and the concentration of the oxidant: the more concentrated the oxidant is, the greater the ratio of acid to aldehyde. Similarly, the higher the reaction temperature, the greater the ratio of acid to aldehyde will be.
Allan Deeds.
2006-10-26 03:40:45 · answer #2 · answered by deedsallan 3 · 1⤊ 0⤋
K2Cr2O7 + 4H2SO4 =
K2SO4 + Cr2(SO4)3 + 3[O] + 4H2O
ch3ch2ch2oh --->[O]---> ch3ch2cho ---> ch3ch2cooh
2006-10-26 03:37:36 · answer #3 · answered by The Potter Boy 3 · 1⤊ 0⤋
The product is H3C-CH2-CH2-CH3. H2 adds across the double bond turning an alkene into the alkane.
2016-03-17 05:43:53 · answer #4 · answered by Anonymous · 0⤊ 0⤋