How many g of Na3PO4 is produced by 75.7g of H3PO4?
2006-10-24 19:05:06 · 4 answers · asked by noodlenmac0329 2 in Science & Mathematics ➔ Chemistry
This is what I have so far:
NaOH + H3PO4 > Na3PO4 + 3H2O
1 mol H3PO4 = 98.0 g
1 mol NaPO4 = 164.0 g
2006-10-24 19:07:52 · update #1
I'm not trying to be mean, but I need help figuring this out. If you can't help me or have no idea what I am talking about, please don't criticize me for trying to learn and asking for help.
2006-10-24 19:12:59 · update #2
I'm not going to give you the answer but look at your equation:
NaOH + H3PO4 ------> Na3PO4 + 3H2O
Can you see the ratio?
1 mole NaOH+ 1 mole H3PO4 -->1 mole Na3PO4+3 moles H2O
1:1:1:3
Now you have the molar mass of H3PO4 and Na3PO4
1 mol H3PO4 = 98.0 g
1 mol NaPO4 = 164.0 g
So you can say 98.0g of H3PO4 gives you 164.0 NaPO4, right?
If 98.0g of H3PO4 gives you 164.0g of NaPO4, how many grams of NaPO4 will you get if you have 75.7g H3PO4?
2006-10-24 19:19:05 · answer #1 · answered by smarties 6 · 1⤊ 1⤋
sorry that I'm lazy and I'm not going to do all the calculations, but I'll tell you what you need to do.
find out how many moles of H3PO4(#grams/GFM) and then find out how many moles of Na3PO4 you get(ie comparing the coefficients in this case it is 1:1 so #molesH3PO4=#molesNa3PO4) and then multiply the moles by the GFM and you will get the grams of Na3PO4
2006-10-25 02:18:29 · answer #2 · answered by fleisch 4 · 1⤊ 1⤋
3NaOH + H3PO4 --> Na3PO4 + 3H2O
mole of H3PO4 = 75.7 / 98 = 0.77 mole
mole of Na3PO4 = 0.77 mole
mass of Na3PO4 = 0.77 * 164 = 126.28 grams
You'll have to try harder next time.
peace
vixklen
2006-10-26 02:18:54 · answer #3 · answered by vixklen 3 · 0⤊ 0⤋
Sorry..but you wont be able to get your education by getting a free ride here..
try your text book?? not geting a free answer.
2006-10-25 02:08:11 · answer #4 · answered by bagaboooooo 1 · 1⤊ 3⤋