simplify this function?

0 ⤊

simplify this function?

( cos(2x+2h) - cos(2x-2h) ) / h

thanks

2006-10-24 18:12:40 · 4 answers · asked by leksa27 2 in Science & Mathematics ➔ Mathematics

4 answers

There is an identity that says:
cosA - cosB = 2sin[(A + B) / 2] * sin[(B - A) / 2]

Letting A = 2x + 2h, and B = 2x - 2h, we have:
(A + B) / 2 = 2x, and (B - A) / 2 = -2h

Therefore, [cos(2x + 2h) - cos(2x -2h)] / h

= 2sin(2x) * sin(-2h) / h

= -2sin(2x) * sin(2h) / h

2006-10-24 23:33:44 · answer #1 · answered by falzoon 7 · 0⤊ 0⤋

=( cos(2x+2h) - cos(2x-2h) ) / h

2006-10-25 01:21:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋

stop cheating and do your own homework!!

2006-10-25 01:33:29 · answer #3 · answered by Anonymous · 0⤊ 1⤋

Equals . . .
åç . . .

2006-10-25 01:28:01 · answer #4 · answered by xinnybuxlrie 5 · 0⤊ 0⤋