How do I solve this problem? You have 30 gallons of a drink that is 25% juice. How many gallons of a drink....

Question

How do I solve this problem?

You have 30 gallons of a drink that is 25% juice. How many gallons of a drink that is 10% juice must be added to produce a drink that is 15% juice?

Thank you!

Answer 1

OK..so you have 30 gallons of juice that is 25% (.25) juice

30(.25) - that is how much juice you have.

Now you want to add "some" gallons of 10% (.10) juice

X(.10) - You don't know how much, but something, we call it X

Finally, you want the result, which is the 30 gallons you started with, plus the X you added.
So, in the end you want 30+X Gallons of 15% (.15) juice

So here goes...

30(.25) + X(.10) = (30+X)(.15)

So you have your 30 at 25%, you add X at 10% and you end with (30 + X) of 15%. Now solve

30(.25) + X(.10) = (30+X)(.15)

7.5 + .1x = 4.5 + .15x

3 = .05x

x = 60

You need to add 60 gallons of 10% juice to get a total of 90 Gallons of 15% juice.

Answer 2

Let x = # of gallons of 10% juice to add. Then want,

(30/4 + x/10) / (30+x) = 15/100 = 3/20.

x=60

Answer 3

If I am reading this right, which I may not, the 30@25% is irrealevant.You'll always have 10%.
unless you are adding the 10% to the 25% in which the answer is around 20 gallons

Answer 4

A+B=30
.25A+.10B=.15(30)
Solve the system

Answer 5

30*0.25 +n*0.10 = (n+30)*0.15
7.5+0.1n = 0.15n + 4.5
0.05n = 3
n = 60 gal.