A boat begins on the east side of a river and heads straight WEST acress the river with a speed of 3.7m/s(realtive to the water). The river flows SOUTH at a speed of 1.8m/s(realtive to the shore). The resultant velocity of the boat (realtive to the shore) is approxmately__m/s at __degrees (CCW from east).
A. 1.90 B. 4.11 C. 5.50 D. 203.6 E. 205.9 F. 209.1
G. 222.0 H.227.7 I. 228.0 J. 240.9 K. 244.1 L. 246.3
M. None of these are even close to the correct magnitude.
N. None of these are even close to the correct direction.
2006-10-24 17:36:03 · 3 answers · asked by "G" 1 in Science & Mathematics ➔ Physics
square root of (1.8^2 + 3.7^2) to get the speed
tan(1.8/3.7) to get angle below the horizontal
2006-10-24 17:43:15 · answer #1 · answered by Arts 6 · 0⤊ 0⤋
The two velocities are at right angles to each other. Use Pythagorean theorem to obtain the resultant.
V^2=3.7^2+1.8^2
=13.69+3.24
V =16.93^1/2
=4.11m/s , (Get the angle, X,whose sin=0.90)
It's heading SXdegreesW. Use
your table of trigonometric functions
to get X.
SinX=3.7/4.11
=0.90
2006-10-25 02:23:48 · answer #2 · answered by tul b 3 · 0⤊ 0⤋
looks like precalculus to me
2006-10-25 00:55:26 · answer #3 · answered by alohadvd 1 · 0⤊ 0⤋