2006-10-24 17:33:23 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
hmmm this is funny
ln(a*b) = ln(a) + ln(b)
now -x = -1 * x
so ln( -1 * x ) = ln(-1) + ln(x)
but ln is only defined for arguments > 0 ....
anyway No it is not coreect what you write.
ln( -x ) = ln(|x|) if x < 0
otherwise ln(-x|) is undefined.
2006-10-24 19:12:03 · answer #1 · answered by gjmb1960 7 · 0⤊ 0⤋
Ln domain only go from 0 to positive infinity. So any type of negative number doesn't extist for Ln.
2006-10-24 17:45:56 · answer #2 · answered by Crellos 2 · 1⤊ 0⤋
-ln(x)=ln(x)^-1= ln(1/x)
You cannot take the log of a negative number so ln(-x) has no meaning.
2006-10-24 17:49:26 · answer #3 · answered by sydney m 2 · 0⤊ 1⤋
no. natural logarithms act in same way as other logarithms. itshoud be Ln(x^-1)= -Ln(x)
2006-10-24 17:38:06 · answer #4 · answered by einstein4j 2 · 2⤊ 0⤋
NO, totally wrong
if x>0, then -x<0 and you CANNOT take the natural log of a negative number.
2006-10-24 17:54:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
My guess is no because I don't think you are allowed to pull a constant outside like that.
2006-10-24 17:36:07 · answer #6 · answered by mrkitties420 4 · 1⤊ 1⤋