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set this up. Can someone show me how?

2006-10-24 16:18:52 · 8 answers · asked by bobbysgirlmeri 2 in Science & Mathematics Mathematics

8 answers

1+1/x / 1-1/x
=(x+1)/x / (x-1)/x
=(x+1)/(x-1)

2006-10-24 16:34:18 · answer #1 · answered by Anonymous · 0 0

Get a common denominator of x in the numerator and denominator:

Numerator:
1 + 1/x --> x/x + 1/x --> (x + 1) / x

Denominator:
1 - 1/x --> x/x - 1/x --> (x - 1) / x

The x cancels out and you have:
(x + 1) / (x - 1)

The graph of the equation is shown below. Note, there are two equations being graphed (the original and the reduced equation) which proves they are equivalent.

If it matters, you have a vertical asymptote at x = 1 and a horizontal asymptote at y = 1...

2006-10-24 23:33:20 · answer #2 · answered by Puzzling 7 · 0 0

1+1/x/1-1/x

x≠0

1+1/x * x/1-1
2/0=undefined

Check:

1+1/0 * 0/1-1
2/0≠0
undefined≠0

2006-10-24 23:32:39 · answer #3 · answered by Anonymous · 0 0

well if it's (1+1/x) / (1-1/x) then if you multiply the top and bottom by x (this will cancel the little fractions in each), you'll get:

(x + 1) / (x - 1), which is the most simplified answer.

2006-10-24 23:26:13 · answer #4 · answered by dws7011 2 · 0 0

first simplify the top. 1 + 1/x = x/x + 1/x = (x+1)/x
likewise the bottom: 1 - 1/x = x/x - 1/x = (x-1)/x
now you have fractions you can divide - just flip the bottom
and multiply

2006-10-24 23:30:26 · answer #5 · answered by banjuja58 4 · 1 0

You really have to put in parentheses so we don't have to guess at what the problem is. It could be interpreted 3 or 4 different ways as you have written it........

2006-10-24 23:35:58 · answer #6 · answered by Steve 7 · 0 0

its 2x over 0

2006-10-24 23:21:58 · answer #7 · answered by Pedo bear lolz 2 · 1 0

2x

2006-10-24 23:28:39 · answer #8 · answered by unique 2 · 0 0

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