A disk with a radial line painted on it is mounted on an axle perpendicular to it and running through its center. It is initially at rest, with the line at (theta0) = -90°. The disk then undergoes constant angular acceleration. After accelerating for 3.1 s, the reference line has been moved part way around the circle (in a counterclockwise direction) to (thetaF) = 130°.
Given this information, what is the angular speed of the disk after it has traveled one complete revolution (when it returns to its original position at -90°)?
2006-10-24 16:06:16 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
If x is angle, w is angular velocity, a is angular acceleration, and t is time, then x = 0.5*a*t^2. So a = 2x/t^2, and you know that x = 130 - (-90) = 220 degrees, and you were given t. Once you have solved for a, you need to solve for t after one revolution. That's t = sqrt(2x/a), where a is what you calculated but x is now 360, a full rotation. With the new t, calculate w = at, where you have found a and t already.
2006-10-24 16:13:34 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋