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It would be with great appreciation to help me.

2006-10-24 15:33:27 · 0 answers · asked by college_guy_la 2 in Science & Mathematics Other - Science

0 answers

north is zero azimuth, clockwise increasing to 360 at north again. You need to break the circle into 4 parts...n-e, e-s, s-w, w-n. if the az is 187 d, it is in the 3rd quadrant...south, 7d west..

.if the bearing is south 70 degrees east, it is in the 2nd quadrant..so it is 30 d from due east plus 90 deg...110 d AZ

2006-10-24 15:41:17 · answer #1 · answered by Ford Prefect 7 · 0 0

Bearing To Azimuth Calculator

2016-12-28 17:49:02 · answer #2 · answered by Anonymous · 0 0

Azimuth To Bearing

2016-11-11 04:40:42 · answer #3 · answered by ? 4 · 0 0

There are multiple meanings to both azimuth and bearing. In the US, azimuth is 0 degrees for north increasing counterclockwise. Jean Meeus, the prominent mathmatical astronomer, insists that azimuth should be start at zero straight south and increase counterclockwise. Both conventions are used.

Bearing can refer to absolute or relative bearing. Absolute bearing is measured identically to the US version of azimuth. Relative bearing is measured relative to your current heading. In relative bearing, 90 degrees is always straight to the starboard (right) side and 270 degrees is off the port (left) side.

2006-10-24 17:38:36 · answer #4 · answered by Pretzels 5 · 0 0

an azimuth is defined as an angle measured clockwise from a base direction....360 degrees always take map face it north. if your facing 10 degrees and want to be facing 180 add 10. well thats all I remember.

2006-10-24 15:39:19 · answer #5 · answered by imphilthe 2 · 0 0

To convert a fraction to a decimal, you just divide the denominator into the numerator, then multiply by 100 For example: ¼ would be 1 ÷ 4 or 0.25 0.25 times 100 = 25% To convert per cents to decimals, you just divide the percentage number by 100. For example: 23% would be 23/100 or 0.23

2016-03-17 06:55:10 · answer #6 · answered by Anonymous · 0 0

Hi. Try this link : http://www.tpub.com/content/engineering/14069/css/14069_439.htm

2006-10-24 15:36:21 · answer #7 · answered by Cirric 7 · 0 0

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