Lol I'm so desperate I even scanned the diagram from my textbook T_T
Here's the link to the diagram: http://i5.photobucket.com/albums/y151/susu_atari/problemnumber13.jpg
The question is: what's the measure of angle ABC?
Well, I figured out that x=3.
But what's the measure of angle ABC?!?!
Oh, and can you tell me how you solved the problem?
Thanks T_T
2006-10-24 14:49:56 · 5 answers · asked by 2 days after my B day :) 2 in Science & Mathematics ➔ Mathematics
just because you put in so much effort....
n^2 + 81 is 90 (because those lines are perp.), so solve for n
then angle abc is just 12n
i dont know where this x is from
2006-10-24 14:53:22 · answer #1 · answered by ajflkajfsalkfsalkfna 3 · 0⤊ 0⤋
12* 3 = 36
2006-10-24 14:57:10 · answer #2 · answered by Alan Turing 5 · 0⤊ 0⤋
Hi. All triangles have 180 degrees (except spherical ones). You have the information for all the angles. Look at the two right triangles and solve them independently. You can do this! Looking again, you need at least ONE side length. I would give you teacher an answer for ACB based on AD =1. Let her prove you wrong. She can't!
2006-10-24 14:56:37 · answer #3 · answered by Cirric 7 · 0⤊ 0⤋
u know the angle ADB is an altitude i.e. 90
therefore n^2+81=90
n^2=9
n=3
ABC angle u have given that = 12n
therefore
12*3=36 degree
2006-10-24 14:58:17 · answer #4 · answered by Anonymous · 0⤊ 0⤋
n^2 + 81 = 90 Therefore n = 3 (I think that's what you found.)
The missing angle is 12n or 36.
2006-10-24 15:00:56 · answer #5 · answered by teacher2006 3 · 0⤊ 0⤋