We dilute 1.00 mL of 1.00 M HCl solution to 100.0 mL. What is [OH-] in this solution at 25°C?

Question

a. 1.00 x 1012 M
b. 1 x 102 M
c. 0.010 M
d. 7.00 x 10-4 M
e. 1.00 x 10-12 M

Answer 1

You diluted the HCl 100 times, thus [HCl]=1/100 =10^-2 M
and because it is a strong acid it dissociates completely giving one H+ per HCl molecule. So [H+]=[HCl]= 10^-2 M

Kw=[H+][OH-]=>
10^-14= 10^-2 * [OH-] =>

[OH-]=10^-12 M

Answer 2

Hcl Solution