how can we prepare 100ml of 0.1M NaCl (mol wt 58.5) solution ?

Question

how can we prepare 100ml of 0.1M NaCl (mol wt 58.5) solution ?

Answer 1

Easily, Molarity is Moles of Solute (NaCl) divided by the number of litres of solution (H2O) therefore,

You begin with the equation
0.1M = x(Moles of Solute)/0.1(Litres)

and solve for "x"
0.01mol =x

Then, you convert 0.01mol of NaCl into grams
weight in grams/0.01mol=58.5grams per mole/1mol
weight in grams=.588g

so you should mix .588 grams of NaCl with 100 mL of water.

Answer 2

0.1 M NaCl = 0.1 mole NaCl/ 1 liter water

0.1 mol NaCl * 58.5 g/mol NaCl = 5.9 g NaCl

* To prepare this solution, first put 5.9 grams of NaCl into a container such as a beaker or graduated cylinder. Then put water in the container until the water gets to the 1 liter mark (or 1000 millileters).

Answer 3

M1V1=M2V2 M1=10, V1=?, M2= .01ml, V2=100ml Do the math

Answer 4

58.5g/mole*0.1mole(since 0.1M is the concn)
= 5.85 g
dissolve the 5.85 g NaCl in 100 mL water...
viola you have now 0.1 M NaCl soln