A park has 2 bike trails in the shape of similar quadrilaterals. Trail A has side lengths of 75m, 93m, 114m and 129m. The shortest side of Trail B is 50m. Luis rides his bike around Trail A once and Tara rides her bike around Trail B twice. Who rode the longest distance and by much?
2006-10-24 12:56:01 · 5 answers · asked by Roberta A 1 in Science & Mathematics ➔ Mathematics
Sides of Trail A are 75m, 93m, 114m and 129m.
Total perimeter = 411m
Trail B:
Scale factor Trail A" Trail B = 75:50 (ratio of shortest sides)
= 3:2
So perimeter of Trail B = 2/3 * 411
= 274 m
Two laps of Trail B = 548 m
Thus Tara rode the longer distance by 137 m
2006-10-24 13:12:30 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
Since the shortest side of Trail A is 75 m and the shortest side of Trail B is 50 m, Trail A is 75/50 = 1.5 times the length of Trail B.
Trail A = 75 + 93 + 114 + 129 = 411 m
Trail B = 411 / 1.5 = 274 m
Twice around Trail B is 548 m, so Tara rode the longer distance by 548 - 411 = 137 m.
2006-10-24 13:03:24 · answer #2 · answered by Steven Jay 4 · 0⤊ 0⤋
If something is 40% smaller, you in basic terms subtract 40%. So 40% of 40 energy is 16: you try this by technique of multiplying 40 by technique of 0.4. the answer might want to be 40 - 16 = 24 A shorter way might want to easily be to multiply by technique of 40 by technique of 0.6, when you consider that it is a million-0.4.
2016-12-05 04:51:09 · answer #3 · answered by reeves 4 · 0⤊ 0⤋
Tara rode her bike 548m
Luis rode his bike 411m
Which means Tara rode 137m more
2006-10-24 13:03:50 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I thought you said it was a "word" problem; Why does this question have numbers in it?
2006-10-24 13:04:48 · answer #5 · answered by grumpyfiend 5 · 0⤊ 1⤋