please tell me how to find the absolute maximum and minimum of (x^3)-(12x^2)-27x+5 When the interval is [2,0]?

Answer 1

f(x) = (x^3)-(12x^2)-27x+5
Possible relative minima or maxima occur when
3x^2 - 24x - 27 = 0
x^2 - 8x - 9 = 0
(x+1)(x-9) = 0
x = (-1,9)
both values lie outside your interval, so
f(0) = 5, absolute maximum
f(2) = 8 - 48 - 54 + 5= -89, absolute mimimum

Answer 2

it equals 0

Answer 3

(x6-7) 4850498502985