4x^2 + 4xy + y^2 / 2x + y
2006-10-24 12:39:11 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
4x^2 + 4xy + y^2 factors into (2x+y)^2
You can cancel one the (2x+y)'s on the top with the one on the bottom leaving you with
2x + y
2006-10-24 12:43:27 · answer #1 · answered by MsMath 7 · 2⤊ 1⤋
I assume you mean (4x^2 + 4xy + y^2) / (2x + y)?
Factor the equation in the numerator to get:
(2x + y)(2x + y) / (2x + y)
At this point you'll realize that you can cancel a '2x + y' from top and bottom, leaving:
2x + y
2006-10-24 19:44:01 · answer #2 · answered by Puzzling 7 · 1⤊ 1⤋
hey
4x^2+4xy+y^2 = (2x+y)(2x+y) break it down!!
so 4x^2+4xy+y^2/2x+y same as (2x+y)(2x+y)/2x+y
cancel (2x+y) out with 2x+y u get (2x+y)
so the answer is 2x+y
gudluk
2006-10-24 19:51:27 · answer #3 · answered by George 1 · 1⤊ 0⤋
(4x^2 + 4xy +y^2)/(2x+y) = ((2x+y)^2)/(2x + y)
(4x^2 + 4xy +y^2)/(2x+y) = 2x+y
2006-10-24 19:46:20 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
divide as usual long division.
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2x+y ! 4x^2 + 4XY + y^2
first term is 2x. Place on top. multiply (2x)(2x+y). put under 4x^2 +4XY. subtract. bring down Y^2.
second term is y. put on top. multiply. subtract.
answer is 2x+y. Neat huh?
2006-10-24 19:50:27 · answer #5 · answered by davidosterberg1 6 · 0⤊ 0⤋
factor out you have: (2x+y)(2x+y)/2x+y
ans: 2x+y
2006-10-24 19:44:07 · answer #6 · answered by 7 · 0⤊ 0⤋
Does it say wha x & y equal?
2006-10-24 19:47:55 · answer #7 · answered by Token_Cocoa 2 · 0⤊ 0⤋