a. An individual that has the genotype AabbCcDd is crossed to one with the genotype AaBbCCdd. Assuming that these genes are unlinked, what fraction of the offspring will have the genotype AAbbCCdd? b. Assume that in each case the dominant allele is represented by the upper case letter. What fraction of the offspring will exhibit the phenotype of all four dominant alleles?
2006-10-24 12:38:51 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Biology
a. 1/4 x 1/2 x 1/2 x 1/2 = 1/32
b. 3/4 x 1/2 x 1/1 x 1/2 = 3/16
2006-10-24 12:56:32 · answer #1 · answered by Anonymous · 0⤊ 0⤋
we know dat contribution of homozygous is 1/2 while dat of heterozygous is 1/4 so for genotype AAbbCCdd we all the homozygous characters hence its total fraction is 1/2 x 1/2 x 1/2 x 1/2 = 1/16. contribution of dominant allele is 3/4 while 4 recessive it is 1/4. so 4 all dominant characters its total fraction is 3/4 x 3/4 x 3/4 x 3/4 = 81/256.
2006-10-25 09:53:18 · answer #2 · answered by vaishali 2 · 0⤊ 0⤋
Some_Dude's right
2006-10-25 03:29:46 · answer #3 · answered by tort_oise 1 · 0⤊ 0⤋