2006-10-24 12:06:19 · 7 answers · asked by Annie Poo 2 in Science & Mathematics ➔ Mathematics
Multiply 3 on both sides:
3(1)=3(83/3-4x/3)
3=83-4x
Subtract 83 on both sides:
-4x=-80
x=20
Check:
1=83/3-4(20)/3
1=83/3-80/3
1=3/3
1=1
I hope this helps!
2006-10-24 13:58:59 · answer #1 · answered by Anonymous · 5⤊ 0⤋
1 = 83/3 - 80/3...so 4x=80....so x=20
2006-10-24 12:11:17 · answer #2 · answered by davidosterberg1 6 · 2⤊ 0⤋
hey Ann,
which standard are u studying?
it is simple:
multiply both sides by common factor 3:
3 = 83 -4x
subtract 3 from both sides and then add 4x to both sides:
0 = 80-4x
4x =80
divide both sides by 4
x = 20
2006-10-24 12:14:06 · answer #3 · answered by anami 3 · 2⤊ 0⤋
1=83/3-4x/3 multiply both sides by three
3=83-4x subtract 83 from both sides
-80=-4x divide both sides by -4
20=x Q.E.D.
2006-10-24 12:09:56 · answer #4 · answered by Andrew M 2 · 2⤊ 0⤋
3=83-4x; -80=-4x; x=20;
2006-10-24 12:11:05 · answer #5 · answered by Anonymous · 2⤊ 0⤋
I would multiply entire equation by 3 leaving
3=83-4x
4x=80
x=20
2006-10-24 12:09:20 · answer #6 · answered by travislizzie 2 · 2⤊ 0⤋
multiply all the equation by 3
3= 83 - 4x
3 - 83 = -4x
80 = 4x
80/4 = x
x = 20
2006-10-24 12:10:21 · answer #7 · answered by Melia 2 · 2⤊ 0⤋