2(4b+20)=56
*First, you distribute the 2 and get rid of the parenthasees.
2x4b=8b 2x20=40
6b+40=56
**Next, subtract 40 from both sides.
8b+40-40(cancels out)=56-40=16
So you get 8b=16
***Now divide by 8 on both sides
16 divided by 8
and get the b=2
2006-10-24 12:10:33
·
answer #1
·
answered by Rocky 4
·
0⤊
1⤋
b=2
2006-10-24 12:13:10
·
answer #2
·
answered by ? 5
·
0⤊
1⤋
2(4b+20)=56
8b + 40 = 56
8b = 56-40
8b = 16
b=2
2006-10-24 12:07:22
·
answer #3
·
answered by pompeii 4
·
0⤊
1⤋
2(4b + 20) = 56
8b + 40 = 56
8b = 16
b = 2
2006-10-24 12:10:43
·
answer #4
·
answered by Meilleur_que_toi 4
·
0⤊
1⤋
8b+40=56
8b=16
b=2
2006-10-24 12:07:56
·
answer #5
·
answered by hannan 3
·
0⤊
1⤋
2(4b+20)=56
Distribute.
8b+40=56
Subtract 40 from both sides.
8b+40-40=56-40
8b=16
Divide each side by 8.
8b/8=16/8
So then:
b=2
Get it now? ^-^
2006-10-24 12:08:46
·
answer #6
·
answered by Anonymous
·
0⤊
1⤋
2(4b+20)=56
8b+40=56
b=2
???? been along time since i did this, not sure its right
2006-10-24 12:10:04
·
answer #7
·
answered by john doe 2
·
0⤊
1⤋
http://mathproblem.com/calculatures/equation
2006-10-24 12:06:47
·
answer #8
·
answered by ♥Roberta. 5
·
0⤊
1⤋