An Eskimo pushes a 50.0 kg sled over level ground with a force of 175 N exerted horizontally, moving a distance of 6.0 m. If the net work done on the sled is 150 J find the coefficient of kinetic friction.
2006-10-24 11:49:08 · 2 answers · asked by terpjenrose 1 in Science & Mathematics ➔ Physics
Work = F*s, where F is the net force in N, and s is the displacement in meters.
Substitute given values:
150=F*6
F=150/6
=25N
But net force is also equal to 175N-force of friction, f.
Therefore,
25=175-f
f=175-25
=150N
Now compute the coefficient of kinetic friction using the formula:
Kinetic friction, f=uR where f is the force of friction in N, u is the coefficient of friction, and R is the weight normal to the surface in N.
Substitute known values:
150=u50*9.8
u=150/50*9.8
=0.306
2006-10-25 02:47:13 · answer #1 · answered by tul b 3 · 4⤊ 0⤋
coefficient of kinetic friction = 0.3058
. . . I think
2006-10-24 12:15:57 · answer #2 · answered by kaloustaphae 1 · 0⤊ 0⤋