seesaw torque?

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A child of mass 38.5 kg is sitting on a horizontal seesaw at a distance of 1.8 m from the supporting axis. What is the magnitude of the torque about the axis due to the weight of the child?

the answer would be nice, but the formulas that id use are what im really looking for.

2006-10-24 11:31:09 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics

2 answers

T(orque) = F(orce) x D(istance from axis)

T = 38.5 * 9.8 * 1.8

T= 679.14 (forgot the unit of measurement though)

2006-10-24 11:41:23 · answer #1 · answered by teh_popezorz 3 · 0⤊ 0⤋

T = Force * moment of inertia (I)

I think...

2006-10-24 18:47:26 · answer #2 · answered by jg 2 · 0⤊ 0⤋