at the same time a pole cast a shadow 22'4" long what is the height of the pole as a decimal number
2006-10-24 11:28:06 · 7 answers · asked by anthonyp 2 in Science & Mathematics ➔ Mathematics
12/8 = x/268
8x = 3216
x = 402 inches
2006-10-24 11:32:20 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
A yardstick is 3 feet long. If the shadow is 5 feet long, then the tangent of the angle you're looking for is 3/5 (0.6). Remember "opposite over adjacent". If the shadow of the flagpole is 39 (195/5) times that of the yardstick, then the height of the flagpole must be 39 times the height of the yardstick. Not giving you the answer, just helping you set it up ;-))
2016-05-22 10:40:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The shaDOW IS 2/3 AS LONG AS THE POLE. Therefore the pole length will be : 22.3333 x 3/2 = 33.49999999995 feet
2006-10-24 11:34:27 · answer #3 · answered by Jo B 2 · 0⤊ 1⤋
use cross mulitiplication
1 foot= 12 inches
22 feet 4 inches = 268 inches
12in/8 in = ?/268 inches
(actual / shadow)
cross multiply... 12 times 268= 8 times ?
3216=8?
?=402 inches
2006-10-24 11:32:54 · answer #4 · answered by reen 2 · 0⤊ 0⤋
Without providing the answer for you:
This is a basic Trig problem, and involves the geometric property of "similar triangles." Draw out the two respective triangles on paper, fill in the blanks (length of each side, and angles of each vertex), and use the appropriate Trig function to find the missing side. This problem should take you less than 5 minutes -- less than 2 with a calculator.
2006-10-24 11:36:20 · answer #5 · answered by MSC 1 · 0⤊ 1⤋
make a proportion!
12 in/8in=x/268in cross multiply!
2006-10-24 11:31:04 · answer #6 · answered by kiddo89 2 · 0⤊ 1⤋
3/2* 22.33=33.495 feet
2006-10-24 11:30:32 · answer #7 · answered by bruinfan 7 · 0⤊ 1⤋