Physics Question?

Question

A train is headed down a track at 25 meters/second. Ahead of the train, at a distance of 10 kilometers, is a rail cart moving down the same track in the same direction at 4 meters/second.

How many seconds will it take for the train to overtake the rail cart?

What equation do I have to use?

Answer 1

You need to use an equation of constant motion for both the train and the rail cart.

future position = current position + velocity * Time

For the train, assuming the train is at current position = 0, you have
fp = 0m + 25m/s * t

For the rail cart, the current position = 10000m and velocity = 4m/s.

fp = 10000m + 4m/s * t

set the two equations equal to each other and solve for t to find out when the train will hit the rail car.

0m + 25m/s * t = 10000m + 4m/s*t

25m/s* t - 4m/s*t = 10000m - 0m

21m/s * t = 10000m

t = 10000/21 s
t = 476.19 seconds

Answer 2

First, simplify it. It only matters how fast the train is gaining on the cart. It's headed for the cart at 21 meters per second. So, it's just simple division. The train has to close a 10,000 meters gap at 21 meters a second.

Answer 3

DT=DC
RTXTT=RCXTC
25TT=40 RC=10 TC=4
TT=2.25 seconds

*DT=distance of train *DC= distance of cart
RT=rate of train TT=time of train
RC=rate of cart TC= time of cart

Answer 4

let x=time;
25*x=10000+4x; x=476 seconds

Answer 5

she asked which equation not what's the answer, phyics equation number 3