2006-10-24 09:11:24 · 12 answers · asked by cody a 1 in Sports ➔ Baseball
It is 90 feet to 2nd and another 90 feet to 3rd making it 180 feet. But if you run across the pitcher's mound then you would be going 127.3 feet. Using Pythagorean theorem of a^2 +b^2 = c^2
2006-10-24 09:15:32 · answer #1 · answered by Aaron 3 · 2⤊ 1⤋
It depends on what you're asking. If it's as the baserunner goes, it's 180 feet. (There are 90 feet between each base.) If it's a straight line, Pythagorus will help you out. A squared + B squared=C squared. 2(90*90)=c squared. 16200=c squared. So, the distance, in a straight line from first to third is 127.27922061357856 feet.
2006-10-24 13:25:42 · answer #2 · answered by pgh9fan 2 · 0⤊ 0⤋
if you're running the bases it would be 180 ft. because the bases are 90 ft. apart but as for a straight shot from first to third I'm not sure.
2006-10-24 09:50:37 · answer #3 · answered by Giants Fan! 4 · 0⤊ 0⤋
Its approximately 127.279 feet from third to first base.
2006-10-24 10:06:49 · answer #4 · answered by phoenix 1 · 0⤊ 0⤋
Aaron is correct. Approximately 127.3 feet based on the Pythagorean theorem.
2006-10-24 09:24:43 · answer #5 · answered by cubswin03 3 · 0⤊ 0⤋
The other two are right on the straight line. But if you are talking about base to base. It would be exactly 180ft.
Thank You
2006-10-24 09:46:31 · answer #6 · answered by reed 2 · 0⤊ 0⤋
127 feet 3 3/8 inches
2006-10-27 17:05:29 · answer #7 · answered by Anonymous · 0⤊ 0⤋
if you go from first to second to third it is 180 feet. if you go in a straight line across the pitchers mound it is 127.3 feet
2006-10-24 09:18:00 · answer #8 · answered by sammy 2 · 1⤊ 0⤋
90 ft
2006-10-24 09:15:10 · answer #9 · answered by Anonymous · 0⤊ 1⤋
in a straight line? Or as the runner plays?
Not to mention that nobody goes from third to first....
Well, they DONT
2006-10-24 09:12:49 · answer #10 · answered by Clarkie 6 · 0⤊ 1⤋