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the sum of two numbers is -2. if twice the smaller number is added to three times the larger the result is one. what are the numbers?

2006-10-24 09:04:36 · 8 answers · asked by diggleM 2 in Science & Mathematics Mathematics

8 answers

x+y=-2
2x+3y=1
solve the first equation for y
y=-2-x
substitute that value for y in the second equation
2x+3(-2-x)=1
simplify
2x-6-3x=1
x=-7
substitute -7 for x in the first equation
-7+y=-2
y=5

x=-7
y=5

2006-10-24 09:14:14 · answer #1 · answered by Anonymous · 0 0

Let me denote the smaller one by a and the larger one by b.

Then,
a+b=-2
2*a+3*b=1.

Subtracting two times the first equation from the second gives:
b=5.
Substituting this back into the first one gives a=-7.
Fortunately, a

2006-10-24 16:08:58 · answer #2 · answered by ted 3 · 0 0

x+y= (-2).....equation 1
2x+3y=1......equation 2
rewrite equation 1 as x=(-2)-y
substitude the rewrite of equation 1 into equation 2
2{(-2)-y}+3y=1 => (-4)-2y+3y=1 => -2y+3y=1+4...add 4 on both sides => y=5.....the value of y
x+y= (-2).....equation 1
substitude the value of y into equation 1
x+5=(-2).=> x=(-2)-5 => x=(-7)

Answer: x= (-7) y=5

2006-10-24 18:22:18 · answer #3 · answered by Anonymous · 0 0

x + y = -2
2x + 3y = 1

Mulitply the first equation by -2

-2x - 2y = 4

Now add the two together

2x +3y = 1
-2x -2y = 4
--------------
0x + y = 5

y = 5
x = -7

2006-10-24 16:10:49 · answer #4 · answered by Dave 6 · 0 0

let the no be x & y
now, x+y=-2 ----------I
let x is smaller and y is larger
now, 2x+3y=1 ------------II

solving equ. I and II by sub.method
we get
x = - 7
y = 5

2006-10-24 16:29:43 · answer #5 · answered by akshat_technogod 1 · 0 0

Um... yeah what they said 5 and -7

2006-10-24 16:14:30 · answer #6 · answered by Bean Dippers 1 · 0 0

that's a good question! x+y=-2 3x+2y=1 is that right?

2006-10-24 16:15:28 · answer #7 · answered by Kent 1 · 0 0

Let the numbers be "x"and "ÿ"
x + y = -2...........................(1)
2x + 3y = 1........................(2)
Solving for x and y
y = 5
and x = -7

2006-10-24 16:24:03 · answer #8 · answered by quark_sa 2 · 0 0

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