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2 answers

Similar to your other reduction of order question. Let y2(x) = y1(x)v(x) for some v. Substitute this into the equation and get

x^(3/2)sin(x) v'' + 2x^(3/2)cos(x)v' = 0.

Let w = v', and divide through by x^(3/2)sin(x), and get

w' + 2cot(x)w = 0

meaning w = exp(-2ln(sin(x)))w0 = csc^2(x)C1, where C1 is a constant. Integrate this to get v = -C1*cot(x) + C2, where C2 is also a constant.

2006-10-25 16:35:43 · answer #1 · answered by James L 5 · 0 0

I am in full agreement with and fully endorse what Mr."Aryan" has stated in his answer which is not only very detailed but very precise ,to the point and very crisp too.

2016-05-22 08:41:04 · answer #2 · answered by Anonymous · 0 0

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