resolves to
(2x+y) * (2x+y) / 2x+y
= 2x+y / 1 = 2x+y
2006-10-24 08:45:45
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answer #1
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answered by cappy 3
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Do you notice anything special about the polynomial 4x^2+4xy+y^2? It's a perfect square! 4x^2 + 4xy + y^2 =
(2x+y)^2. Then (2x+y)^2 / (2x+y) = 2x+y, which is your answer. Just a tip: Whenever you have a polynomial in the denominator (bottom), like 2x+y, check to see if it is a factor of the polynomial on the top. Best of luck.
2006-10-25 23:31:53
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answer #2
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answered by MathGuy 2
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The answer is 2x + y....
(2x+y) * (2x+y) = 4x^2 + 4xy + y^2
FOIL-First,Outer,Inner,Last
2006-10-24 15:48:09
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answer #3
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answered by JMKroeg 1
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2x+y
_____________
2x+y / 4x^2+4xy+y^2
4x^2+2xy
_______________
0 +2xy+y^2
2xy+y^2
_____________
0
therefore: the answer is 2x +y
check by multiplying.
may not see it quite good but i show complete solution here. look closely
2006-10-24 15:46:39
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answer #4
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answered by minaco 2
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What kind of help? You didnt say. I get really astounted, so many people post messages on the Math section asking for help and don't say what the question is!
2006-10-24 15:40:40
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answer #5
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answered by Steiner 7
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What is the problem.?
If you make this equal to zero,it is the equation of a second degree curve.
What do you want?
Do you want to plot the curve?
2006-10-24 15:59:23
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answer #6
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answered by curious 4
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(4x^2+4xy+y^2)/(2x+y)
=(2x+y)(2x+y)/(2x+y)
=2x+y
i hope that this helps
2006-10-24 16:44:21
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answer #7
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answered by Anonymous
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need more info?
shouldnt there be an "equation" as in an = ?
2006-10-24 15:44:17
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answer #8
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answered by Anonymous
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is this an equation or what?
2006-10-24 15:39:41
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answer #9
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answered by mozakkera 2
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