Before I answer, I want to note that if the logarithm has a SUBSCRIPT, it typically means that the logarithm has the subscript as a base. For example, natural log (usually written ln) is a logarithm with base e, so it could be written log_e, where the _ denotes a subscript.
In your case, with a superscript, it depends on who is writing it. Most likely,
ln^2 x = (ln x)^2 = (ln x)*(ln x)
This notation (a superscript on the function) became popular to use in trigonometry with sin(x) and cos(x) functions, where sin^2(x)=sin(x)*sin(x). Since then, people often use it with other functions.
However, more formal mathematicians typically say that (with an exception made for the trig functions),
ln^2(x) = ln( ln( x ) )
In other words, ln^2 means that the operation "ln" was applied to "x" twice. For example, remember that in linear algebra, if you have an n-by-n matrix A and an n-by-1 vector x, the multiplication:
A*x
Since this results in another n-by-1 vector A*x, it can be thought of as the matrix A "operating" on x, and sometimes it is written:
A(x)
However, since A(x) (or A*x) represents another n-by-1 vector, A can also operate on A(x) (or A*x). If A operates on A*x, then it could be written as:
A*A*x = A^2 x
Now, you might want to write the thing on the left as A(A(x)). However, then that means you'd want to write the thing on the right as A^2(x). Thus, A(A(x))=A^2(x). Hence, the superscript notation does not refer to "squaring" the A(x). Instead, it refers to A operating on x "twice."
If you're in an upper-level math class, you will probably use the latter definition (which many mathematicians would argue is "more correct"). Otherwise, if you're an average non-mathematician, you will probably use the former definition.
2006-10-24 08:25:56
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answer #1
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answered by Ted 4
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It means a typo or bad notation.
Maybe you mean log (base 2) of x?
The way that it is written does not make sense since you cannot raise ln to a power (ln is the name of the function).
2006-10-24 08:11:25
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answer #3
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answered by raz 5
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it means
(ln x) (ln x)
ln(x^2) is totally different from (ln x) (ln x) = ln^2 (x)
2006-10-24 08:13:13
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answer #4
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answered by Anonymous
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it doesn't mean anything
ln function requires an arguement
In this case ln is raised to 2 (x) which means no arguement for ln
2006-10-24 08:12:51
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answer #5
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answered by Sushain T 1
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