please solve the equation for y,?

Question

l. 10x-4y=13
2. 4x + 7y = 14
3. 2x-3y+6 =0
4. -2x + 3y + z = 15
5. 9x + 4z = 7 + 8y

Answer 1

y=(10x-13)/4
y=(14-4x)/7
y=(-2x-6)/3
y=(2x-z+15)/3
y=(9x+4z-7)/8

Basic algebra. Learn it, hate it but PASS!

Answer 2

l. 10x-4y=13

Using add, subtract, multiply or divide, perform the same operation on both sides of the equation to produce the form

y = expression

- 4y = - 10 x + 13 {subtract 10 x}
y = (- 10x + 13)/(-4) { divide by -4}
y = 5x/2 - 13/4

2. 4x + 7y = 14
7y = -4x + 14 {subtract 4x}
y = - 4x/7 + 2 {divide by 7}

You should be able to do the rest of these

3. 2x-3y+6 =0
4. -2x + 3y + z = 15
5. 9x + 4z = 7 + 8y

Answer 3

l. 10x-4y=13

y = (13 - 10x) / -4

2. 4x + 7y = 14

y = (14 - 4x) / 7

3. 2x-3y+6 =0

y = ( -6 - 2x) / -3

4. -2x + 3y + z = 15

y = (15 + 2x - z) / 3

5. 9x + 4z = 7 + 8y

y = (9x + 4z - 7) / 8

Answer 4

This question isn't too difficult, we need to factorise. Just ask yourself: what two factors of 66 add to give 17? Well, factor pairs of 66 include: 2 and 33, 6 and 11, 3 and 22. Obviously 6 and 11 are the answer. So the factorisation is: (y - 11)(y - 6) = 0 y = 11 or 6 That is, unless you didn't just miss the y there, and you actually wanted to factorise: y^2 - 17 + 66 = 0 y^2 + 49 = 0 y^2 = -49 This has no real solution, since we can't have the square root of a negative.

Answer 5

1. (13 - 10x) / (-4)
2. (14 - 4x) / 7
3. (2x + 6) / 3
4. (2x + 15 - z) / 3
5. (9x + 4z - 7)/ 8

Answer 6

1. y= (-1/4)(13-10x)
2. y=(1/7)(14-4x)
3. y=(-1/3)(6-2x)
4. y=(1/3)(15+2x-z)
5. y=(1/8)(9x+4z-7)

Answer 7

1. add or subtract terms to isolate the variable, y
2. divide every term by the coefficient of the variable, y
3. pat your self on the back. You did your own homework.