dropped penny?

Question

if a penny is dropped from a building and lands on the ground at 6 seconds. What is the height of the building?

Answer 1

The acceleration due to gravity on the Earth's surface at sea level is equivalent to 1 g (pronounced gee) which is a non-SI unit of acceleration defined as exactly 9.80665 m/s2 (almost exactly 32.174 ft/s2)
We can say that distance travelled = initial velocity * total time + 1/2 *acceleration * total time^2

or

s = ut + 1/2at^2

Since the penny was stationary before falling u = 0.

The height of the building is unknown, s = ?.

Since we are at ground level the gravitational field strength is a
constant, so a = 9.80665 m/s^2

The time is given as 6 sec so t = 6

Now,
s = 0 t + 1/2 (9.80665 x 6^2)

Thus s = 176.5197 m

Answer 2

These calculations are correct assuming the penny is falling through a vacuum. In air, the penny would reach a terminal velocity within 6 seconds. without additional info, you can't calculate the height of the building (but it would be lower that the vacuum calculation)

Answer 3

The first second the penny traveled 9.86 meters. The second second it travel 9.86 x2 meters. The third second it travel 9.86 x3 meters...now finish up and add the distances.

Answer 4

falls at 8.6 or 6.8 per somethign i forget