2006-10-24 07:18:10 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Mohr's salt is ammonium sulfate, (NH4)2SO4. Do you mean "N factor," as in "nitrogen factor"? It's not exactly clear what that is. One resource indicates that the factor is what you have to multiply the mass of N by to get the mass of the substance. In that case, the total molecular mass of (NH4)2SO4 is 2*N + 8*H + S + 4*O = 2*14 + 8*1 + 32 + 4*16 = 132. The atomic mass of just the nitrogen is 2*14 = 28. 132 / 28 = 4.71, so that's your N factor.
2006-10-24 07:28:04 · answer #1 · answered by DavidK93 7 · 1⤊ 7⤋
The n factor of Mohr's salt is 1.
2014-05-16 17:20:48 · answer #2 · answered by Apurv Gupta 1 · 3⤊ 1⤋
n factor is not N factor , it is total transfer in electron.
n factor of mohr salt is 2
2015-05-11 21:59:25 · answer #3 · answered by Neoni Badwa 1 · 0⤊ 0⤋
n-factor of mohr s sal i.e. FeSO4.(NH4)2SO4 (Ferrous mmonium Sulphate) = total cationic charge or total anionic charge.
Both ways u can do it either cationic or anionic
if u calculate the total cationic charge =( Fe2+ + 2NH4 1+) = 2*1+2*1 = 4
if u calculate the total anionic charge= (2SO4 2-) = 2*2=4
therefore n-factor of mohr s salt = 4
2016-08-15 04:54:09 · answer #4 · answered by PRAKRITI 1 · 0⤊ 0⤋
the n factor is 2 as the number of positive or negative charges
SO4 has 2- two
(NH4)2 has 2 * 1+ two here also
2006-10-24 08:06:17 · answer #5 · answered by Sushain T 1 · 0⤊ 3⤋
Mohrs salt is - FeSO4(NH4)2.SO4. 6H2O
and the n factor is 6H2O
2006-10-26 16:42:27 · answer #6 · answered by scientian 2 · 0⤊ 3⤋